Question 1134526
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Let x be the rate of the freight train, in miles per hour (the value under the problem's question).


Then the time equation is


    {{{348/(x+23)}}} = {{{210/x}}}.


Solve it for x. Start cross-multiplying


    348x = 210*(x+23),

    348x = 210*x + 210*23

    x = {{{(210*23)/(348-210)}}} = 35.


<U>Answer</U>.  The freight train rate is 35 miles per hour.
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Solved.


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If you have questions regarding my solution, send me a message through the "Thank you" window/form.


In this case, refer to the problem's ID number, which is 1134526.


Otherwise, I will not know to whom to answer.
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