Question 1134521
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<pre>
Let x be that time for Bobby (the value under the problem's question).


Then the time for Billy alone is  (x-35) minutes.


Now,   Bobby makes  {{{1/x}}}  of the job per minute,

while  Billy makes  {{{1/(x-35)}}}  of the job per minute.


Working together,  they make  {{{1/x}}} + {{{1/(x-35)}}}  of the job per minute.

Their combined rate is exactly  {{{1/76}}}  of the total job, which gives you an equation


    {{{1/x}}} + {{{1/(x-35)}}} = {{{1/76}}},      (1)


and now it is <U>your job</U> to solve it !


The first step in solving is to multiply both sides of the equation (1)  by  76*x*(x-35).


You will get a quadratic equation then, and I wish you to get a full success in solving it !
</pre>


Happy calculations !


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To see many similar solved problems, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Using-quadr-eqns-to-solve-word-problems-on-joint-work.lesson>Using quadratic equations to solve word problems on joint work</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this textbook under the topic 
"<U>Rate of work and joint work problems</U>" &nbsp;of the section &nbsp;"<U>Word problems</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.