Question 1134506
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The center has x-coordinate  {{{(-3+2)/2}}} = -0.5  and y-coordinate  2.


The diameter is {{{sqrt(2-(-3)^2 + (2-2)^2)}}} = {{{sqrt(5^2)}}} = 5.


The radius is  {{{5/2}}} = 2.5.


So the standard equation of the circle is 


    {{{(x+0.5)^2}}} + {{{(y-2)^2}}} = {{{2.5^2}}}.
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