Question 1134506
{{{d=sqrt((2-(2))^2+(2-(-3))^2)}}}
{{{d=sqrt(25)}}}
{{{d=5}}}

If diameter = 5, radius = 2.5 because radius is half of diameter.

Now, we need to find the center of the circle, which is midpoint between the two given points. 

Midpoint = ((-3+2)/2, (2+2)/2)
         = (-1/2, 2)

The equation of a circle: 
{{{(x-h)^2+(y-k)^2=r^2}}}         (h,k) is the center and r = 5/2

We found center to be (-1/2,2) and radius = 5/2:

Solution: {{{(x+(1/2))^2+(y-2)^2=25/4}}}  



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