Question 1134471
{{{2^(1/2)}}}, {{{4^(1/3)}}}, {{{6^(1/4)}}} in ascending order 

{{{sqrt(2)}}}, {{{root(3,4)}}}, {{{root(4,6)}}}

=>approximately: {{{sqrt(2)=1.41}}},{{{root(3,4)=1.59}}}, {{{root(4,6)=1.57}}}

in descending order ( from the largest to the smallest  number):

{{{highlight(4^(1/3) > 6^(1/4 )>2^(1/2))}}}


in ascending order ( from the smallest to the largest number):

{{{highlight(2^(1/2)<6^(1/4 )<4^(1/3))}}}