Question 1134468
perimeter is equal to 2 times length + 2 times width.


let L = length
let W = width
let P = perimeter


P = 2L + 2W = 2 * (L + W)


you are given that the length is one meter more than twice the width.


that makes L = 2W + 1.


in the formula P = 2 * (L + W), replace L with 2W + 1 to get:


P = 2 * (2W + 1 + W)


simplify to get P = 2 * (3W + 1)


simplify further to get P = 6W + 2


you are given that the perimeter is equal to 302 meters.


that makes P = 302 which makes P = 6W + 2 which becomes 302 = 6W + 2


subtract 2 from both sides of that equation to get 300 = 6W


solve for W to get W = 300 / 6 = 50


since L = 2W + 1, then L = 101.


you have L = 101 and W = 50


P = 2 * (L + W) becomes P = 2 * (151) which becomes P = 302.


solution looks good.


solution is the length is equal to 101 and the width is equal to 50.