Question 1134443
Under the given conditions, the overlapping area is a quadrilateral with four
vertices: (0,0) (0,3) (3,6) and (6,0)

*[illustration Four]

Substitute each into the C=-3x+5y to see which one gives the highest value.

If (0,0):

C=0

If (0,3):

C = 0 + 5(3) = 15

If (3,6): 

C = -3(3)+5(6) = -9+30 = 21

If (6,0): 

C = -3(6) + 5(0) = -18

Maximum occurs at C=21 when x = 3 and y = 6.


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