Question 1134438
We will set up two equations with two unknowns here. 

Let dime = d, which is worth $0.1 each
Let nickels = n, which is worth $0.05 each

$0.1d + $0.05n = $2.75                  - equation (1)
d = 2n                                  - equation (2)

Substitute d = 2n into the first equation:

$0.1(2n) + $0.05n = $2.75
$0.2n + $0.05n = $2.75
$0.25n = $2.75
n = 11

d = 2n = 22

She has 11 nickels and 22 dimes. 


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