Question 1134427
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You have received, so far, three responses to your question, showing similar algebraic solutions.  Here is another quite different method that I like to use on this kind of problem.<br>
The ratio of times required is 2.5:3, or 5:6.
Since the distances are the same, that means the ratio of the speeds is 6:5.
If the ratio of the two speeds is 6:5 and the difference between the two speeds is 10mph, then the two speeds are 50mph and 60mph.<br>
The distance is then rate times time: 2.5 hours at 60mph = 150 miles; or 3 hours at 50mph = 150 miles.