Question 1134421


If {{{log(2)}}}, {{{log(2^(x-1))}}} and {{{log(2^(x+1))}}} are in A.P, find the value of {{{x}}}. 


If these are in AP, then 


{{{log(2^(x-1))-log(2) = log(2^(x+1))-log(2^(x-1)) }}}


{{{(x-1) log(2)-log(2) = (x+1)log(2)-(x-1)log(2) }}}


{{{((x-1)-1)log(2) = ((x+1)-(x-1))log(2) }}}


{{{(x-1-1)cross(log(2) )= (x+1-x+1)cross(log(2) )}}}


{{{x-2= 2}}}


{{{x=4}}}