Question 1134427
Normally it takes John 2.5 hours to drive from his house to his office.
 Due to yesterday's snowy weather he was driving 10 mph slower than usually, and it took 3 hours.
 How many miles is the office away from John's house?
:
let s = speed normally
then
(s-10) = speed in the snow
the distance of both trips are the same,
 write a distance question: dist = speed * time
3(s-10) = 2.5s
3s - 30 = 2.5s
3s - 2.5s = 30
.5s = 30/.5
s = 60 mph
:
Find the distance
2.5 * 60 = 150 mi
confirm the dist using the slower speed
3 * 50 = 150 mi