Question 1134416
Standard form: y=ax^2+bx+c     
It's important to know what b is when completing the square.

Vertex form: y=a(x-h)^2+k          (h,k) is the vertex



{{{y=2x^2-12x+22}}}
{{{y=2(x^2-6x)+22}}}    1. Factor out 2 to make sure the coefficient of x^2 = 1

{{{y=2(x^2-6x+9-9)+22}}}    2. Add and subtract (b/2)^2 inside the parentheses
{{{y=2(x-3)^2-18+22}}}      3. Factor into the form of (x-b)^2
{{{y=2(x-3)^2+4}}}       This is the vertex form.



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