Question 1134406
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<pre>
Let "n" be the number of chickens he bought (the value under the question).


Then the price for one chicken is  {{{60/n}}}.


Had he bought (n+5) chickens for the same money, the price for one chicken in this hypothetical case would be  {{{60/(n+5)}}}.


From the condition,


    {{{60/n}}} - {{{60/(n+5)}}} = 2.


It is your basic equation to solve.


    Looking into the equation, you can guess its solution mentally and momentarily:  n = 10.


To solve it algebraically, multiply both sides by n*(n+5). You will get


    60*(n+5) - 60n = 2n*(n+5)

    60n + 300 - 60n = 2n^2 + 10n

    2n^2 + 10n - 300 = 0

    n^2 + 5n - 150 = 0

    (n-10)*(n+15)) = 0.


Of two roots  n= 10  and  n= -15, only positive  n= 10 is meaningful.


<U>Answer</U>.  n= 10 chickens.
</pre>

Solved.


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To see many other similar solved problems, &nbsp;look into the lessons

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/misc/Had-they-sold.lesson>Had they sold . . .</A>

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