Question 1134392
<pre>
                              VERTICAL LEG   HORIZ LEG    HYPOTENUSE

Initial Ladder, Triangle       y+0.25         1.5          h

Stepped Ladder, Triangle        y             2.0          h
</pre>

{{{system((y+0.25)^2+1.5^2=h^2,y^2+2^2=h^2)}}}

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Equating the two expressions for h^2 and solving gives {{{y=3.375}}}.

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{{{h=sqrt(y^2+4)}}}

{{{h=sqrt(3.375^2+4)}}}

{{{approximately}}}{{{highlight_green(3.923)}}},{{{ladder}}}