<PRE><B>Question 1134352</B>
Find 3 consecutive odd integers
a, (a+2), (a+4)
 if the difference of the squares of the least and greatest is 120.
(a+4)^2 - a^2 = 120
FOIL (a+4)(a+4)
a^2 + 8a + 16 - a^2 = 120
8a = 120 - 16
a = 104/8
a = 13 is the 1st odd integer
then, obviously 
15 and 17 are the next two
:
:
Check on your calc: 17^2 - 13^2 =</PRE>