Question 1134279
Use the Binomial Probability Formula
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Probability (P) (k successes in n trials) = nCk * p^(k) * (1-p)^(n-k), where nCk = n!/(k! * (n-k)!), p is probability of success
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For this problem, p = 0.84, n = 20
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a) P (k = 5, n = 20) = 20C5 * (0.84)^5 * (1-0.84)^(20-5) = 0.000001
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b) P (k > or = 6, n = 20) = 1 - (summation i = 0 to 5 of P(k = i, n = 20) = 0.999999
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c) P (k < or = 4, n = 20) = summation i = 0 to 4 of P(k = i, n = 20) = 0.000001
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d) P (5 < or = k < or = 8, n = 20) = summation i = 5 to 8 of P(k = i, n = 20) =  0.000012
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