Question 1134207
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<pre>
if  9^x = 3^(x-1) / 2^(x+1),    then


{{{3^(2x-(x-1))}}} = {{{2^(-(x+1))}}},   or, equivalently,


{{{3^(x+1)}}} = {{{2^(-(x+1))}}},        or, equivalently


{{{3^(x+1)}}}.{{{2^(x+1)}}} = 1,         or, equivalently


{{{6^(x+1)}}} = 1,


which implies   


x + 1 = 0,    or  x= -1.      <U>ANSWER</U>.
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