Question 1134080
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Consider the line y = -3/-2 x +6.
Find the equation of the line that is perpendicular to this line and passes through the point (-9,-3). 
Find the equation of the line that is parallel to this line and passes through the point (-9,-3).
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Your given line is the same as {{{y=3x/2+6}}}.


Slope for the perpendicular line is  {{{-2/3}}}.
Slope for the parallel line is  {{{3/2}}}.


You might choose the point-slope equation form to find the two lines asked for.
{{{system(y+3=(-2/3)(x+9),and,y+3=(3/2)(x+9))}}}