Question 1134073

slope-intercept form: {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

the equation of the line that passes through ({{{-3}}}, {{{-1}}}) and has a slope of{{{m= 2/5}}} will be:

{{{y=mx+b}}}........plug in given data and find {{{b}}}

{{{-1=(2/5)(-3)+b}}}

{{{-1=-6/5+b}}}

{{{-1+6/5=b}}}

{{{-5/5+6/5=b}}}

{{{b=1/5}}}

now we have a slope of{{{m= 2/5}}} and y-intercept {{{b=1/5}}} and your 

equation is:{{{y=(2/5)x+1/5}}} 


{{{drawing( 600, 600, -10, 10, -10, 10,

circle(-3,-1,.12),locate(-3,-1,p(-3,-1)),
 graph( 600, 600, -10, 10, -10, 10,(2/5)x+1/5)) }}}