Question 1134073
What is the equation of the line that passes through (-3,-1) and has a slope of 2/5? Put your answer in slope-intercept form.
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Use y-y1 = m*(x-x1) where m = slope and (x1,y1) is the point
y+1 = (2/5)*(x+3)
y = (2/5)x + 6/5-1
y = (2/5)x + 1/5
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slope-intercept form is
y = mx + b
m = slope = 2/5
b = y-intercept = 1/5 or (0,1/5)