Question 1134025
I used a normal distribution to determine the probability.  

z = (0.50 - 0.53)/sq rt (.53*.47/2000)

The 0.50 is representing the less than half that we want painted.  .53 is the percent of homes that were painted white.  .47 is the q value, or percent that are not painted white.

z = -2.68

From a z-table area = .0037

P(p < 50%) = .0037