Question 1134021
----
----
find the value of k so the equation 3x²+kx-2=0 has roots whose sum is equal to 6. 
----
----


{{{highlight(k=-18)}}}


-


{{{-k/3=6}}}

{{{k=(-3)*6}}}

{{{k=-18}}}

-


---------
k so the equation 2x²+(4-k)x-17=0 has roots equal but in opposite sign
---------


HINT:  Think about how the graph of the function should be.


If one root is r, then other root is -r.
Lookup on your own or derive for yourself, sum of roots of quadratic equation.
{{{r+(-r)=0=(k-4)/2}}}

{{{k=4}}}.