Question 1133977

{{{sin(-4x)sin(-2x)=0}}}

Solving each part separately:

{{{sin(-4x)=0}}}......use the period {{{2pi*n}}}to find the full set of all solutions, 

assuming {{{n=1}}}

{{{-4x=0+2pi*n}}}=>{{{x=0/-4+(2pi*n)/-4}}}=>{{{x=-(pi*n)/2}}}

{{{-4x=pi +2pi*n}}}=>{{{x=pi/-4+(2pi*n)/-4}}}=>{{{x=-pi/4-(pi*n)/2}}}



{{{sin(-2x)=0}}}

{{{-2x=0+2pi*n}}}=>{{{x=0/-2+(2pi*n)/-2}}}=>{{{x=-pi*n }}}

{{{-2x=pi +2pi*n}}}=>{{{x=pi/-2+(2pi*n)/-2}}}=>{{{x=-pi/2-pi*n}}}

if {{{n=0}}}=>{{{x=0}}} in both cases

Combine all the solutions:

{{{x=-(pi*n)/2}}}, {{{x=-pi/4-(pi*n)/2}}}, {{{x=-pi*n}}} ,{{{x=-pi/2-pi*n}}},{{{x=0}}} for any integer {{{n}}}




{{{ graph( 600, 600, -5, 5, -5, 5,sin(-4x)sin(-2x)) }}}