Question 1133959
Look at the probability 0, 1, 2 will have such an inspection rating, then subtract that from 1 to give the probability of having at least 3
for 0, it is 0.91^7=0.517
for 1 it is 7*0.91^6*0.09=0.358
for 2 it is 7C2*0.91^5*0.09^2=9=0.106
These three add to 0.981, so 1-0.981=0.019  ANSWER