Question 1133916

the point-slope formula: {{{y-y[1]=m(x-x[1])}}}

if ({{{x[1]}}}, {{{y[1]}}}) = ({{{-2}}}, {{{10}}}) and ({{{x[2]}}}, {{{y[2]}}}) = ({{{3}}}, {{{-5}}}) are points on the line, slope is

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(-5-10)/(3-(-2))}}}

{{{m=(-15)/(3+2)}}}

{{{m=(-15)/5}}}

{{{m=-3}}}


=> {{{y-y[1]=-3(x-x[1])}}}....plug in coordinates of one point


{{{y-10=-3(x-(-2))}}}

{{{y-10=-3(x+2)}}}

{{{y-10=-3x-6}}}

{{{y=-3x-6+10}}}

{{{y=-3x+4}}}=> your line

{{{drawing( 600, 600, -15, 15, -15, 15,
circle(-2,10,.12), locate(-2,10,p(-2,10)),
circle(3,-5,.12), locate(3,-5,p(3,-5)),
 graph( 600, 600, -15, 15, -15, 15, -3x+4)) }}}