Question 1133915

Find the equation of the line using the point-slope formula.

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept



if line is perpendicular to line {{{5y = x -4}}}, it has a slope negative reciprocal to a slope of the line {{{5y = x -4}}}

a slope of the line {{{5y = x -4}}}=>{{{y = (1/5)x -4/5}}} is {{{1/5}}}=>negative reciprocal is {{{-1/(1/5)=-5}}}

so far your line is {{{y=-5x+b}}}


 and if passes through the point ({{{-2}}}, {{{1}}}), use it to find {{{b}}}


{{{1=-5(-2)+b}}}

{{{1=10+b}}}

{{{1-10=b}}}

{{{b=-9}}}


your line is {{{y=-5x-9}}}



{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-2,1,.12), locate(-2,1,p(-2,1)),
 graph( 600, 600, -10, 10, -10, 10, -5x-9, (1/5)x -4/5)) }}}