<PRE><B>Question 103288</B>
Graph the parabola (y+2)^2 + 6x + 3 = 0. Identify the vertex, focus, and the equation of the directrix. 
------------------
Write in vertex form:
(y+2)^2 = -6(x-(1/2))
Vertex: ((1/2),-2)
-----------------------------------------------------
4p=-6, so p =-3/2
Focus: ((1/2)-(3/2),-2) = (-1,-2)
------------------------------------
Directrix: x = (1/2)-(-3/2) ; x = 2
-------------------------------------
Cheers,
Stan H.

</PRE>