Question 1133897
From how it appears, this is (2/3)-i/(2i+1/2)
rewrite as (2/3)-i/((1/2)+2i)
multiply top and bottom by conjugate ((1/2)- 2i)
numerator is ((2/3)+i)((1/2-2i)=(1/3)-(4/3)i+(1/2)i-2i^2=(1/3)-(5/6)i+2 or (7/3)-(5/6)i
denominator is (1/4)+4 or 17/4
This is [4(7/3)-(10/3)i]/17