Question 1133863
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This kind of problem can be solved informally using logical reasoning.<br>
(1) Set aside the 11 "extra" dimes.  What remains is equal numbers of dimes and nickels with a total value of $2.60-$1.10 = $1.50.
(2) The value of one dime and one nickel is 15 cents, or $0.15.
(3) To make the remaining $1.50, the number of dimes and nickels required is $1.50/$0.15 = 10.<br>
So there are 10 nickels and 10+11=21 dimes.