Question 1133862
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The integers:  {{{system(x-1, x, x+1)}}}


{{{(x+1)^2}}} = {{{22+x(x-1)}}}

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{{{x^2+2x+1}}}= {{{x^2-x+22}}}
{{{2x+1=22-x}}}
{{{3x+1=22}}}
{{{3x=21}}}


x = 7.


<U>ANSWER</U>.  The integers are  6, 7, and 8.


SOLVED.