Question 103282
A good example is a can. Take note that it has TWO CIRCULAR bases. Something else happens when you 'unwrap' the can. It will make you a RECTANGLE with a length equal to the CIRCUMFERENCE of one base and a WIDTH equal to the HEIGHT of the cylinder.

Thus,
surface area =area of two bases + the area of the rectangle

area of the two bases={{{2*pi*r^2}}}

area of the rectangle={{{(2*pi*r)*h}}}

      where r=radius
            h=height

Thus,

surface area={{{2*pi*r^2}}}+{{{(2*pi*r)*h}}}

Substituting r=4 and h=7,

S.A.={{{2*pi*4^2}}}+{{{(2*pi*4)*7}}}
    ={{{88*pi}}}