Question 1133761
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The area of any triangle is 


Area = {{{(1/2)*a*b*sin(gamma)}}}


where a and b are any two sides and {{{gamma}}} is the angle between them.


In given case, the sides are of the length of x centimeters, and the area is maximal when the anle {{{gamma}}} is 90 degrees.


So, the area is maximal when the triangle is isosceles right angled triangle, and then the area is 


{{{Area[max]}}} = {{{(1/2)x2}}}.


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Completed and solved.