Question 1133757


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in your case {{{a=y}}}

 apothem is {{{sqrt(2)y/2+y/2=(sqrt(2)y+y)/2=y(sqrt(2)+1)/2}}}


distance between two parallel sides is twice the length of apothem

{{{distance=2*y(sqrt(2)+1)/2}}}

{{{distance=cross(2)*y(sqrt(2)+1)/cross(2)}}}

{{{distance=y(sqrt(2)+1)}}}