Question 1133688
{{{z=r(cos(alpha)+i*sin(alpha))}}}

given:

{{{6-6i=a-b*i}}}

{{{6(1-i)=a-b*i}}} =>{{{a=1}}}, {{{b=-1}}}

{{{r=sqrt(a^2+b^2)}}}
{{{r= sqrt(2)}}} 

{{{z=6*sqrt(2) (cos(alpha)+i*sin(alpha))}}}


{{{tan(alpha)=b/a=-1/1=-1}}}

{{{alpha = arctan(-1)+2pi=7pi/4}}}


{{{z = 6* sqrt(2) (cos(7pi/4) + i *sin(7pi/4))}}}