Question 1133649
<pre>
x¶y means {{{(x/y)-x^2}}}.  Therefore

2/3¶4/5 means {{{((2/3)/(4/5))-(2/3)^2}}}

{{{((2/3)/(4/5))-(2/3)^2}}}{{{""=""}}} 

{{{(2/3)*(5/4)-(4/9)}}}{{{""=""}}} 

{{{10/12-4/9}}}{{{""=""}}} 

{{{5/6-4/9}}}{{{""=""}}} 

LCD = 18

{{{expr(5/6)*expr(3/3)-expr(4/9)*expr(2/2)}}}{{{""=""}}} 

{{{15/18-8/18}}}{{{""=""}}} 

{{{7/18}}}

Edwin</pre>