Question 1133609

Prove that (5,x,x+1)are Pythagorean triplets
<pre>x CANNOT be the longest side (hypotenuse) since it's smaller than x + 1
Therefore, using x + 1 as hypotenuse, you'll get the following equation: {{{matrix(1,3, (x + 1)^2, "=", x^2 + 5^2)}}}, and the pythagorean triple: 5-12-13.
Using 5 as the hypotenuse, you'll get the following equation: {{{matrix(1,3, 5^2, "=", x^2 + (x + 1)^2)}}}, and the pythagorean triple: 3-4-5, when the POSITIVE (> 0) value of x is chosen.