Question 1133526


let's two integers be {{{x}}} and {{{y}}} where {{{x}}} is the larger integer

if the sum of two integers is {{{74}}} we have

{{{x+y=74}}}........eq.1


if the larger is {{{26}}} more than {{{twice}}} the smaller, we have

{{{x=2y+26}}}..........eq.2

substitute it in eq.1


{{{2y+26+y=74}}}........eq.1...solve for {{{y}}}

{{{3y=74-26}}}

{{{3y=48}}}

{{{y=48/3}}}

{{{highlight(y=16)}}}


go back to {{{x=2y+26}}}..........eq.2 substitute {{{y}}} value

{{{x=2*16+26}}}

{{{x=32+26}}}

{{{highlight(x=58)}}}


so, your integers are: {{{highlight(58)}}} and {{{highlight(16)}}}