Question 1133459
Are both x^2+16 and x^3+27 factorable? Why or why not (explain).
<pre>Sum of squares({{{matrix(1,3, x^2 + 16, or, (x)^2 + (4)^2)}}}) CANNOT be factored with INTEGERS. 
{{{x^3 + 27}}} follows the SUM OF CUBES method of factoring, or {{{matrix(1,3, a^3 + b^3, "=", (a + b)(a^2 - ab + b^2))}}}, to factor to: {{{highlight_green((x + 3)(x^2 - 3x + 9))}}}