Question 1133419

{{{ 0.15(x+40)-0.08(x-60)=15}}}.........first multiply

{{{ 0.15x+0.15*40-0.08x-0.08(-60)=15}}}

{{{ 0.15x+6-0.08x+4.8=15}}}

{{{ 0.15x-0.08x=15-6-4.8}}}

{{{ (0.15-0.08)x=4.2}}}

{{{ 0.07x=4.2}}}

{{{ x=4.2/0.07}}}...both numerator and denominator multiply by {{{100}}} to get rid of decimals

{{{ x=420/7}}}

{{{ x=420/7}}}

{{{ x=60}}}