Question 103202
3y^2-7x-5=0
using the quadratic equation: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
y=(7+-sqrt[-7^2-4*3*-5])/2*3
y=(7+-sqrt[49-60])/6
y=(7+-sqrt109)/6
y=(7+-10.44)/6
y=(7+10.44)/6
y=17.44/6
y=2.907 answer.
y=(7-10.44)/6
y=-3.44/6
y=-.573 answer.