Question 1133341
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The traditional algebraic solution method....<br>
20% of x ounces, plus 60% of 600 ounces, equals 30% of (x+600) ounces.<br>
{{{.20(x)+.60(600) = .30(x+600)}}}<br>
The equation is easily solved with basic algebra.<br>
I leave that to you....<br>
A faster path to the solution of any mixture problem like this involving two ingredients....<br>
30% is 1/4 of the way from 20% to 60%.  (The distance from 20% to 60% is 40%; the distance from 20% to 30% is 10%; 10% is 1/4 of 40%.)<br>
That means 1/4 of the alloy must be the higher percentage.<br>
The 600 ounces of 60% copper are 1/4 of the total, so the total is 600*4 = 2400 ounces; that means 1800 ounces of the 20% alloy.