Question 1133274
probability is 1/3 for each urn.
for urn 1: (1/3)(6/11)=6/33 or 2/11
for urn 2:(1/3)(1/2)=1/6
for urn 3:(1/3)(1/3)=1/9
The probability is the sum with LCD 198
(1/198)(36+33+22)or 91/198 or 0.4596