Question 1133269
(3t-5)^2-11(3t-5)+10=0  Let x=3t-5
then x^2-11x+10=0
and (x-10)(x-1)=0
x=10 and x=1
3t-5=10
3t=15
t=5

3t-5=1
3t=6
t=2