Question 1133213
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The rabbit makes 3 jumps at the same time as the dog makes 2 jumps.

Hence, the rabbit makes 9 jumps at the same time as the dog makes 6 jumps.

But 6 dog's jumps equate to 14 rabbit's jumps.

Hence, at the same time as rabbit makes 9 jumps, the dog moves forward for the distance of 14 rabbit's jumps.


Thus every time as the rabbit moves forward for his 9 jumps, the dog is in 5 = 14 - 9 rabbit's jumps closer to him.


It implies that as soon as the rabbit completes his 9*12-th jump (= 108-th jump), the dog will catch up the rabbit.   


    Notice 12 = 60/5.
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<U>Answer</U>.  &nbsp;As soon as the rabbit makes his &nbsp;108-th jump, &nbsp;the dog will catch up the rabbit.


Or, &nbsp;in the terms of dog's jumps, &nbsp;as soon as the dog makes his &nbsp;6*12 = 72-th jump, &nbsp;the dog will catch up the rabbit. 


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To see other similar solved problem, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/A-rabbit-and-a-dog.lesson>A rabbit and a dog</A> 

in this site.