Question 102942
x^2 - x/ x^2 + 3x + 2 / x^2-1/x^2+2X
:
Assume you mean:
{{{((x^2-x))/((x^2+3x+2))}}}
-------------
{{{((x^2-1))/((x^2+2x))}}}
:
Can be factored to:
{{{(x(x-1))/((x+2)(x+1))}}}
-------------
{{{((x-1)(x+1))/(x(x+2))}}}
:
Invert the dividing fraction and multiply:
{{{(x(x-1))/((x+2)(x+1))}}} * {{{(x(x+2))/((x-1)(x+1))}}}
:
CAncel the (x-1)'s and (x+2)'s and you have:
{{{x/((x+1))}}} * {{{x/((x+1))}}} = {{{x^2/((x+1)^2)}}}