Question 1132891
Poisson with parameter 10
p(0)=e^(-10)*10^0/0!=e^(-10) or 0.00005
p(1)=e^(-10)*10^1/1!=0.0005
p(2)=e^(-10)*10^2/2!=0.0023
probability of fewer than 3 calls is 0.0029
p(10)=e^(-10)*10^10/10!=0.1251