Question 1132938

if the length {{{L}}} of a rectangle is {{{3ft}}} longer than its width {{{W}}}, we have

{{{L=W+3ft}}}.......eq.1

if the perimeter {{{P}}}  of the rectangle is {{{70ft}}}, we have

 {{{P=2(L+W)}}} 

{{{70ft=2(L+W)}}}
 
{{{70ft/2=L+W}}} 

{{{35ft=L+W}}} ......eq.2

substitute {{{L}}} from eq.1 

{{{35ft=W+3ft+W}}} ......eq.2

{{{35ft-3ft=2W}}}

{{{32ft=2W}}}

{{{W=  32ft/2}}}

{{{W= 16ft}}}

go back to eq.1,substitute {{{W}}} 

{{{L=16ft+3ft}}}.......eq.1

{{{L=19ft}}}


answer: its length is {{{19ft}}} and width is {{{ 16ft}}}