Question 1132919

 the length of the oval track is equal to sum of two lengths of the rectangle (each {{{96m}}}) and circumference {{{C=2r*pi}}} of the circle (you got two  semicircles on each end)


assuming that the semicircle is on the {{{48m}}} end then: radius will be {{{48m/2=24m}}}

and the length will be:

{{{L=2*96+2*3.14*24}}}

{{{L=192+3.14*48}}}

{{{L=192+150.72}}}

{{{L=342.72m}}} =>ans. for the length 

the area enclosed by the track will be equal to the area of  rectangle plus the area of circle:


{{{A=48m*96m+3.14(24m)^2}}}

{{{A=4608m^2+3.14(576m^2)}}}

{{{A=4608m^2+1808.64m^2}}}

{{{A=6416.64m^2}}}...=> ans. for the area