Question 1132819
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<pre>

  x^2 + 5xy + y^2 = (x^2 + 2xy + y^2) + 3xy = (x+y)^2 + 3xy = 


        now substitute x+y = 4 and xy = -12 to get


= {{{4^2 +3*(-12)}}} = 16 - 36 = -20.       <U>ANSWER</U>
</pre>

Solved.