Question 1132811
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Let P  = # of balloons Piglet got;

    E  = # of balloons Eyeore got;

    PG = # of <U>GREEN</U> balloons Piglet got;   and

    ER = # of <U>RED</U>   balloons Eyeore got.


Do not worry that I introduced 2-letter designations for two amounts; they are not the products; they are single values;
I introduced them INTENTIONALLY for your easier reading and understanding.


Then we have these equations from the condition:

    P =  E + 3     (1)     ("Piglet got three more balloons then Eeyore did")

   ER = PG + 2     (2)     ("Eeyore got two more red balloons than the number of green balloons Piglet got")


Or,  <U>EQUIVALENTLY</U>,

    P = E +  3     (1')

   PG = ER - 2     (2')

----------------------------------Now subtract equation (2') from equation (1'). You will get

   P- PG = E - ER + 5.    (3)


But  (P - PG)  is the number of Piglet's  RED balloons    (which I will denote as PR from now), while

     (E - ER)  is the number of Eyeore's  GREEN balloons  (which I will denote as EG thereafter).    


So, you have now

    from (2) :  ER = PG + 2,   (4)    ( <<<---=== same as (2) )

    from (3) :  PR = EG + 5.   (5)    ( <<<---=== it is (3) in the formula form )


Now add two equations  (4) and (5).  You will get

               ER + PR = PG + EG + 7.    (6)


Now notice that (ER + PR) is the total number of RED balloons, while  (PG + EG) is the total number of GREEN balloons.


Thus from (6) you get the

<U>ANSWER</U> to the problem's question:  Pooh  brought  7 more RED balloons than GREEN balloons.
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Solved.


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Very nice problem : &nbsp;&nbsp;thanks for posting it &nbsp;&nbsp;! !